**Q1. The perimeter of a rectangular field is thrice the perimeter of a square field. If one of the sides of the square field is 24 m and breadth of the rectangular field is 48 m then find the area of the rectangular field?**

**(a) 4276 Sq m (b) 5354 Sq m (c) 3892 Sq m (d) 4608 Sq m**

**Ans. - (d) Solution: - here P of rectangular = 3 x P of square**

**Or 2(L + 48) = 3 x 4 x 24**

**So L = 144 – 48 = 96 m**

**Area of Rect. = 96 * 48 = 4608 Sq m**

**Q2. The radius of the circle is equal to two-fifth of the side of the square. The area of the circle is 616 sq cm. Find the perimeter of a square?**

**(a) 152 cm (b) 166 cm (c) 140 cm (d) 178 cm**

**Ans.- (c) Solution :- Here R = 2/5 * a ( Let Side of Square = a)**

**And π * R**

^{2}= 616**So R = (616*7 /22)**

^{1/2 }= 14 cm**Side of Square = a = 14*5/2 = 35 cm**

**Perimeter of Square = 35*4 = 140 cm**

**Q3. If the length of a rectangle is increased by 20% while the breadth of the rectangle is decreased by 10% then find percentage change in area of the rectangle?**

**(a) 12 % decreased (b) 8 % decreased (c) 12 % increased (d) 21 % increased**

**Ans.- (b) Solution:- let initial length and breadth of rectangle is L and B**

**So Area = L*B**

**a/c to Question L’ = 6L/5 and B’ = 9B/10**

**So Area = 6L/5 X 9B/10 = 54LB/50**

**Change in Area = 54LB/50 – LB = 4LB/50**

**% Change = 4LB/50LB * 100 = 8%**

**Q4. Find the volume of a cylinder, whose radius is one-fourth of the radius of a circle having an area of 2464 cm2. Height of the cylinder is double of its radius?**

**(a) 2156 cm**

^{3}(b) 2564 cm^{3}(c) 2272 cm^{3 }(d) 2678 cm^{3 }**Ans.- (a) Solution Let Radius of Circle be r and Radius of Cylinder be R**

**So π * r**

^{2}= 2464 Or r = (2464*7/22)^{1/2 }= 28 cm**R = ¼ * 28 = 7 cm**

**And Height = 2R = 14 cm**

**So Volume = 22/7 * 7 * 7 * 14 = 2156 cm**

^{3}**Q5. The area of a rectangular plot is 432 sq cm. The length is 3 times the breadth. If the cost of fencing the plot is Rs. 8 per cm, then find the total cost to fence the plot?**

**(a) Rs. 768 (b) Rs. 716 (c) Rs. 724 (d) Rs. 652**

**Ans. – (a) Solution:- Here L = 3B**

**And L * B = 432**

**Or 3B * B = 432 or B = 12 cm**

**And L = 3 * 12 = 36 cm**

**Perimeter = 2*(12 + 36) = 96 cm**

**Total cost = 8 * 96 = 768 Rs.**

## 0 Comments