RRB Group D Maths Questions: 5th April 2020

Directions(Q1-Q5): Study the following table and answer the questions given below:

Q1. How many students have scored the lowest marks in two or more subjects?

(A) 2                     (B) 3                      (C) 1                     (D) None

Ans. (A)   Solution :-      Charu has scored lowest in S. St and Sanskrit

                                        Vishal has scored lowest in Science and Phy.Edu.

Q2. Who has scored the highest marks in all the subjects together?

(A) Deepak                   (B) Charu                (C) Anupama            (D) Garima

Ans.  (C)  Solution: - Total marks of students

                                       Anupama: 525

                                       Bhaskar: 468

                                      Charu: 412

                                      Garima: 474

                                      Vishal: 361.

                                      Deepak: 437

Q3. What is the precentege of Deepak's marks in all the subjects together?

  (A) 88.63                  (B) 72.83              (C) 67.83                  (D) 62.83

Ans. - (B)   Solution: -   Total marks = 600

                                     Marks scored by Deepak= 437

                                    Percentage = (437/600)*100 = 72.83

Q4. Marks obtained by Charu in Hindi are what percentage of marks obtained by Anupama in

the same subject?

   A) 75.92              (B) 78.38               (C) 77.29              (D) 75.29

Ans.- (D)  Solution:- Percentage is (64/85)*100 = 75.29%

Q5. What are the average marks obtained by all the students together in Science?

(A) 55.75                   (B) 57.50                (C) 60                  (D) 59.50

Ans.- (B)   Solution:-    Total marks in science = 345

                                    Average = 345/6 = 57.5

Q6. Simplify

        (1+1/4)(1-1/4)(1+1/5)(1-1/5)(1+1/6)(1-1/6) = ?

(A) 3/8            (B)5/8                   (C) 7/8                   (D) 1/8

Ans. - (C)   Solution: - Here   = (1-1/16)(1-1/25)(1-1/36)

                                               = (15/16) (24/25) (35/36) = 7/8

Q7. If x + y –z = m And if  x – y + z = n then x is equal to

 (a) (m+n) /2                   (b) m - n                     (c) 2m + n                          (d) m + n

                                              

Ans (A) Solution  :-  By Adding 2x = (m+n)

                                      So x = (m+n) /2