Directions(Q1-Q5): Study the
following table and answer the questions given below:
Q1. How many students have scored the lowest marks in
two or more subjects?
(A)
2 (B) 3 (C) 1 (D) None
Ans. (A) Solution :- Charu has scored lowest in S. St and
Sanskrit
Vishal
has scored lowest in Science and Phy.Edu.
Q2. Who
has scored the highest marks in all the subjects together?
(A)
Deepak (B) Charu (C) Anupama (D) Garima
Ans. (C) Solution: - Total marks of students
Anupama:
525
Bhaskar:
468
Charu: 412
Garima: 474
Vishal: 361.
Deepak: 437
Q3.
What is the precentege of Deepak's marks in all the subjects together?
(A) 88.63 (B) 72.83 (C) 67.83 (D) 62.83
Ans. - (B) Solution: - Total marks = 600
Marks scored by Deepak= 437
Percentage = (437/600)*100 = 72.83
Q4. Marks obtained by Charu in Hindi are what percentage
of marks obtained by Anupama in
the
same subject?
A) 75.92 (B) 78.38 (C) 77.29 (D) 75.29
Ans.- (D) Solution:-
Percentage is (64/85)*100 = 75.29%
Q5. What
are the average marks obtained by all the students together in Science?
(A)
55.75 (B) 57.50 (C) 60 (D) 59.50
Ans.- (B) Solution:- Total marks in science = 345
Average = 345/6 = 57.5
Q6.
Simplify
(1+1/4)(1-1/4)(1+1/5)(1-1/5)(1+1/6)(1-1/6) = ?
(A) 3/8 (B)5/8 (C) 7/8 (D) 1/8
Ans. - (C) Solution: -
Here = (1-1/16)(1-1/25)(1-1/36)
= (15/16) (24/25) (35/36) = 7/8
Q7. If
x + y –z = m And if x – y + z = n then x
is equal to
(a) (m+n) /2 (b) m - n (c) 2m + n (d) m + n
Ans (A) Solution :- By Adding 2x = (m+n)
So x =
(m+n) /2
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