**Time & Work Contractor Questions**

**Q1. A contractor undertook to do a piece of work in 150 days. He employs 50 men to complete the work, but after 90 days, he finds that 25% of the work had been completed. How many more employee should be added to finish the work on scheduled time?**

**Solution:**

Let the number of additional employee = x

Since, M

_{1}D_{1}/W_{1}= M_{2}D_{2}/W_{2}
(50*90)/(1/4)=(50+x)(60)/(3/4)

X=175

**Q2. A contractor undertook to complete a piece of work in 300 days. He employs 100 men to complete the work, but after 180 days, he finds that one-fourth of the work had been completed. How many more employee should be added to finish the work 30 days earlier?**

**Solution:**

Let the number of additional employee = x

Since, M

_{1}D_{1}/W_{1}= M_{2}D_{2}/W_{2}
(100*180)/(1/4)=(100+x)(90)/(3/4)

X=500

**Q3. A contractor undertakes to make a road in 40 days. He employs 16 men to complete the work, but after 30 days, he finds that one-third of the work had been completed. How many more employee should be added to finish the work 6 days late?**

**Solution:**

Let the number of additional employee = x

Since, M

_{1}D_{1}/W_{1}= M_{2}D_{2}/W_{2}
(16*30)/(1/3)=(16+x)(16)/(2/3)

X=44

**Q4. A contractor undertook to do a piece of work in 75 days. He employs 25 men to complete the work, but after 45 days, he finds that 1/3 of the work had been completed. How many more employee should be added to finish the work on scheduled time?**

**Solution:**

Let the number of additional employee = x

Since, M

_{1}D_{1}/W_{1}= M_{2}D_{2}/W_{2}
(25*45)/(1/3)=(25+x)(30)/(2/3)

X=50

**Q5. A contractor undertook to complete a piece of work in 100 days. He employs 20 men to complete the work, but after 75 days, he finds that one-fifth of the work had been completed. How many more employee should be added to finish the work 5 days earlier?**

**Solution:**

Let the number of additional employee = x

Since, M

_{1}D_{1}/W_{1}= M_{2}D_{2}/W_{2}
(20*75)/(1/5)=(20+x)(20)/(4/5)

X=280
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